Question

I have a calculus question about derivatives:$\frac{ - 3sin(x)}{ 10x {}^1 {}^0{ - 6} {} }$

Answer 1

we have the expression

$\frac{-3sin(x)}{10x^{10}-6}$

Applying the quotient rule

The derivative is equal to

$\frac{-3s\imaginaryI n(x)}{10x^{10}-6}=\frac{(-3sin(x))^{\prime}(10x^{10}-6)-(-3sin(x))(10x^{10}-6)^{\prime}}{(10x^{10}-6)^2}$$\frac{(-3cos(x))(10x^{10}-6)+(3s\imaginaryI n(x))(100x^9)}{(10x^{10}-6)^2}$$\frac{-30x^{10}cos(x)+18cos(x)+300x^9sin(x)}{(10x^{10}-6)^2}$