Question

A concave lens creates a virtualimage at -47.0 cm with amagnification of +1.75. What isthe object distance?(Mind your minus signs.)(Unit = cm)

Answer 1

Answer:

Object distance = 26.86 cm

Explanation:

Given:

Image distance, v = -47.0 cm

Magnification, M = 1.75

Object distance, u = ?

$\begin{gathered} M=\frac{|v|}{|u|} \\ \\ 1.75=\frac{47.0}{u} \\ \\ u=\frac{47.0}{1.75} \\ \\ u=26.86\text{ cm} \\ \end{gathered}$

Object distance = 26.86 cm