Question

The equation below describes a circle. What are the coordinates of the centerof the circle?(x-4)2 + (y+12)2 = 17²OA. (-4,12)OB. (4,-12)OC. (-4,-12)OD. (4,12)

Answer 1

Given:

The equation of the circle is:

$(x-4)^2+(y+12)^2=17^2$

Required:

Find the coordinates of the center of the circle.

Explanation:

The equation of the circle when the center is (a,b) and radius is r is given as:

$(x-a)^2+(y-b)^2=r^2$

Compare the given equation with the standard equation we get

a =4, b = -12 and r =17

So the center of the circle is:

$(4,-12)$

F