Problem 11a) Find the average of 12, 0, 4, 1,8onb) The average of 5 numbers is 5. four of the numbersare 5.3, 7. 8. Then the fourth number must beiveQuestion 121 pts

We will have the following:
a) We will have that the average will be:
[tex]x=\frac{12+0+4+1+8}{5}\Rightarrow x=4.6[/tex]b) We will have that the missing number is:
[tex]5=\frac{5+3+7+8+a}{5}\Rightarrow25=23+a[/tex][tex]\Rightarrow a=2[/tex]