Given the slope and a point below;
[tex]\begin{gathered} m=4 \\ (-8,12)\Rightarrow x_1=-8,y_1=12 \end{gathered}[/tex]By using the point-slope equation formula as described below
[tex]y-y_1=m(x-x_1)[/tex]We can obtain the equation of the line with the above formula, we will have to substitute for y1, x1 and m. This process is shown below;
[tex]\begin{gathered} y-12=4(x-(-8)) \\ y-12=4(x+8) \end{gathered}[/tex]By using distributive property, we can remove the bracket and simplify to obtain the equation
[tex]\begin{gathered} y-12=4(x)+4(8) \\ y-12=4x+32 \\ y=4x+32+12 \\ y=4x+44 \end{gathered}[/tex]Hence, the equation of the line with slope of 4 and passing through the point (-8 , 12) is y = 4x + 44