The formula for the area of a trapezoid is A=1/2(b1+b2)xh. When this equation is solved for b1, ins equation is
b1=2A/h-b2.
which is the equivalent equation to find b1?
A=1/2(b1+b2)h times 2 both sides 2A=(b1+b2)h distribute 2A=hb1+hb2 minus 2A both sides 0=hb1+hb2-2A minus hb1 from both sides -hb1=hb2-2A times -1 hb1=2A-hb2 divide both sides by h b1=(2A/h)-b2 not sure what you are asking
