The diagonals of parallelogram ABCD intersect at point E. To prove that

Solution:
Given that;
The diagonals of parallelogram ABCD intersect at point E.
To prove that,
[tex]\angle BAE\cong\angle DCE[/tex]All the options can be used for the proof except;
The sum of the measures of the interior angles is 360°
Hence, the answer is option A