Given
ZA and ZB are supplementary angles. If mZA= (3x + 9)° and m ZB = (6x + 27)°,
Solution
Two angles are called supplementary when their measures add up to 180 degrees
Now,
[tex]\begin{gathered} m\measuredangle A=(3x+9)^0 \\ \\ m\measuredangle A=(3\times16)+9)^0 \\ \\ m\measuredangle A=(48+9)^0 \\ m\measuredangle A=57^0 \end{gathered}[/tex]