Question

Write the equation of the line that passes through (4,-2) and (-4,-4)A) y = 1/4x - 3B) y = 3/4x - 5C) y = - 2D y = - 3/4x + 1

Answer 1

Let:

$\begin{gathered} (x1,y1)=(4,-2) \\ (x2,y2)=(-4,-4) \end{gathered}$

The slope of the line is given by:

$m=\frac{y2-y1}{x2-x1}=\frac{-4-(-2)}{-4-4}=\frac{-2}{-8}=\frac{1}{4}$

Using the point-slope equation:

$\begin{gathered} y-y1=m(x-x1) \\ y+2=\frac{1}{4}(x-4) \\ y+2=\frac{1}{4}x-1 \\ y=\frac{1}{4}x-1-2 \\ y=\frac{1}{4}x-3 \end{gathered}$

Answer:

A) y = 1/4x - 3