We are given the following equation and are asked to put it onto a slope-intercept form:
[tex]2x+4y=16.[/tex]
The slope-intercept form of this type of equation looks like:
[tex]y=mx+b,[/tex]
where m and b are real constants.
In order to get our equation into this form, we will first subtract 2x from both sides of it:
[tex]2x+4y-2x=16-2x,[/tex][tex]4y=-2x+16.[/tex]
(In the picture, the 16 on the right side of the equation got considered as 16x, which lead to the incorrect result of 14x).
Next, we divide both sides by 4:
[tex]\frac{4y}{4}=\frac{-2x+16}{4},[/tex][tex]y=-\frac{2x}{4}+\frac{16}{4},[/tex][tex]y=-\frac{1}{2}x+4.[/tex]
And that is the slope-intercept form of the original equation.
