Given that the side of the prism is 10 cm.
Then, the TSA of the pyramid is given as
[tex]\begin{gathered} TSA=\sqrt{3}a^2 \\ where\text{ a is the side of the prism.} \end{gathered}[/tex]On putting the values
[tex]\begin{gathered} TSA=\sqrt{3}\times10\text{ sq cm} \\ TSA=10\sqrt{3}\text{ sq cm} \end{gathered}[/tex]Therefore the required total surface area is 10√3 sq cm.