Question

Using the quadratic formula, solve:3p^2 - p - 3 = 0

Answer 1

Answer:

x = 1.18 or x = -0.85

Explanation:

Given the equation:

$3p^2-p-3=0$

Solving using the quadratic formula:

$x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

Here, a = 3, b = -1, c = -3

$\begin{gathered} x=\frac{-(-1)\pm\sqrt[]{(-1)^2-4(3)(-3)}}{2(3)} \\ \\ =\frac{1\pm\sqrt[]{1+36}}{6} \\ \\ =\frac{1\pm\sqrt[]{37}}{6} \end{gathered}$

Therefore,

$\begin{gathered} x=\frac{1+\sqrt[]{37}}{6} \\ \\ =1.18 \end{gathered}$

OR

$\begin{gathered} x=\frac{1-\sqrt[]{37}}{6} \\ \\ =-0.85 \end{gathered}$