Respuesta :

Answer:

x = 1.18 or x = -0.85

Explanation:

Given the equation:

[tex]3p^2-p-3=0[/tex]

Solving using the quadratic formula:

[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]

Here, a = 3, b = -1, c = -3

[tex]\begin{gathered} x=\frac{-(-1)\pm\sqrt[]{(-1)^2-4(3)(-3)}}{2(3)} \\ \\ =\frac{1\pm\sqrt[]{1+36}}{6} \\ \\ =\frac{1\pm\sqrt[]{37}}{6} \end{gathered}[/tex]

Therefore,

[tex]\begin{gathered} x=\frac{1+\sqrt[]{37}}{6} \\ \\ =1.18 \end{gathered}[/tex]

OR

[tex]\begin{gathered} x=\frac{1-\sqrt[]{37}}{6} \\ \\ =-0.85 \end{gathered}[/tex]

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