Consider the following system of linear equations:
Equation 1:
[tex]-3x+2y=4[/tex]Equation 2:
[tex]6x\text{ - 2y = -10}[/tex]Adding 2 times equation 1 to equation 2, we get:
[tex](6x\text{ - 2y \rparen+2\lparen-3x +2y\rparen= -10 + 2\lparen4\rparen}[/tex]this is equivalent to:
[tex]6x\text{ -2y -6x +4y = -10 +8}[/tex]this is equivalent to:
[tex]\text{ - 2y + 4y = -2}[/tex]this is equivalent to:
[tex]2y=\text{ - 2}[/tex]solving for y, we obtain:
[tex]y=\text{ -}\frac{2}{2}\text{ = - 1}[/tex]now, replacing this value in equation 2, we get:
[tex]6x\text{ - 2\lparen -1\rparen = -10}[/tex]this is equivalent to:
[tex]6x+2=\text{ -10}[/tex]solving for 6x, we get:
[tex]6x\text{ = -10 -2 = -12}[/tex]solving for x, we obtain:
[tex]x\text{ = -}\frac{12}{6}=\text{ -2}[/tex]we can conclude that the correct answer is:
Answer:The solution of the given system of equations is:
[tex](x,\text{ }y)=\text{ \lparen-2, -1\rparen}[/tex]that is:
[tex]x\text{ = -2}[/tex]and
[tex]y\text{ = -1}[/tex]