Respuesta :

Explanation:

Consider the following system of linear equations:

Equation 1:

[tex]-3x+2y=4[/tex]

Equation 2:

[tex]6x\text{ - 2y = -10}[/tex]

Adding 2 times equation 1 to equation 2, we get:

[tex](6x\text{ - 2y \rparen+2\lparen-3x +2y\rparen= -10 + 2\lparen4\rparen}[/tex]

this is equivalent to:

[tex]6x\text{ -2y -6x +4y = -10 +8}[/tex]

this is equivalent to:

[tex]\text{ - 2y + 4y = -2}[/tex]

this is equivalent to:

[tex]2y=\text{ - 2}[/tex]

solving for y, we obtain:

[tex]y=\text{ -}\frac{2}{2}\text{ = - 1}[/tex]

now, replacing this value in equation 2, we get:

[tex]6x\text{ - 2\lparen -1\rparen = -10}[/tex]

this is equivalent to:

[tex]6x+2=\text{ -10}[/tex]

solving for 6x, we get:

[tex]6x\text{ = -10 -2 = -12}[/tex]

solving for x, we obtain:

[tex]x\text{ = -}\frac{12}{6}=\text{ -2}[/tex]

we can conclude that the correct answer is:

Answer:

The solution of the given system of equations is:

[tex](x,\text{ }y)=\text{ \lparen-2, -1\rparen}[/tex]

that is:

[tex]x\text{ = -2}[/tex]

and

[tex]y\text{ = -1}[/tex]

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