Question

Is the following Linear, Exponential, or Neither? 3,6,12,24,48,...

Answer 1

Explanation

In a linear relationship, the y-values have equal differences. and

In an exponential relationship, the y-values have equal ratios.

so

Step 1

find the common difference ( if there is )

$\begin{gathered} \text{difference}1=\text{ 6-3=3} \\ \text{difference}2=12-6=6 \\ \text{difference3=}24-12=12 \\ \text{difference}4=48-24=24 \end{gathered}$

we can see the diffrence is not the same, so

it is not liear

Step 2

check the common ratio

$\begin{gathered} \text{ratio }_1=\frac{6}{3}=2 \\ \text{ratio }_2=\frac{12}{6}=2 \\ \text{ratio }_3=\frac{24}{12}=2 \\ \text{ratio }_4=\frac{48}{24}=2 \end{gathered}$

so, the ratio is common,

therefore, the answer is

Exponential