To solve the problem we will use the probability function of the binomial distribution, also called the Bernoulli distribution function, is expressed with the formula:
[tex]P(x)=\frac{n!}{(n-x)!\cdot x!}\cdot p^x\cdot q^{n-x}[/tex]Where:
• n, ,=, the number of trials
,• x, = the number of successes desired
,• p, = probability of getting a success
,• q, = probability of getting a failure
Identify in the problem our variables to replace in the distribution:
[tex]\begin{gathered} n=25 \\ x=2 \\ p=0.09 \\ q=1-p \\ q=0.91 \end{gathered}[/tex]Replace in the equation of the distribution:
[tex]\begin{gathered} P(2)=\frac{25!}{(25-2)!\cdot2!}\cdot(0.09)^2\cdot(0.91)^{25-2} \\ P(2)=\text{ }0.278 \end{gathered}[/tex]