Consider the following general periodic function:
[tex]y=a\sin b(\theta\text{ -h})\text{ +k}[/tex]where
a= amplitude
b = frecuency
h= phase translation
k= vertical translation
2π/ |b| = period
Now, consider the following periodic function:
[tex]y=3sin(\theta\text{ -}\frac{\pi}{2})[/tex]Applying the definition given at the beginning of this explanation, we can see that:
a = amplitude = 3
2π/ |b| = period = 2π/|1| = 2π
Then, the graph of the given function is:
Notice that the greatest and least values of y are 3 and -3 respectively.
We can conclude that the correct answer is:
Answer:Graph:
Period:
[tex]2π[/tex]Amplitude:
[tex]3[/tex]The greatest value of y (coordinate y of the maximum point):
[tex]3[/tex]The least value of y (coordinate y of the minimum point):
[tex]\text{ -3}[/tex]