Question

Number 99. A bullet is fired from the ground making an angle of 20 degwith the horizontal with a speed of 1500 m/s.How far (horizontally) will it fall? (1 point)A. O 80062.025 mB. O 147578.788 mC. O25126.105 mD. O 112231.316 mE. O 190655.097 m10. A bullet is fired from a 40 m tall building with a speed of1400 m/s making an angle of 80 deg with the horizontal.Calculate the vertical component of its velocity by the time it hitsA. O-421.75 m/sB 0-2552 599 m/s

Answer 1

Answer:

B. 147578.788 m

Explanation:

The horizontal distance can be calculated as

$R=\frac{v^2\sin(2\theta)}{g}$

When v is the speed, θ is the angle, and g is the gravity.

Replacing v = 1500 m/s, θ = 20, and g = 9.8 m/s², we get:

$\begin{gathered} R=\frac{1500^2\cdot\sin(2\cdot20)}{9.8} \\ \\ R=147578.788 \end{gathered}$

Therefore, the answer is

B. 147578.788 m