Question

Suppose you have an opaque bag filled with 6 red, 4 green, 7 blue and 5 purple balls.6. What is the probability of randomly pulling a blue ball from the bag, returning it, and pulling a red ball on your second pull?7. What is the probability of randomly pulling a purple ball from the bag, returning it, and pulling a blue ball on your second pull?

Answer 1

SOLUTION:

Step 1:

In this question, we are given the following:

Suppose you have an opaque bag filled with 6 red, 4 green, 7 blue and 5 purple balls.

6. What is the probability of randomly pulling a blue ball from the bag, returning it, and pulling a red ball on your second pull?

7. What is the probability of randomly pulling a purple ball from the bag, returning it, and pulling ablue ball on your second pull?

Step 2:

PART 6:

We have 6 red, 4 green, 7 blue and 5 purple balls

Total = 6 + 4 + 7 + 5 = 22

The probability of randomly pulling a blue ball from the bag, returning it, and pulling a red ball on your second pull =

$\frac{7\text{ }}{22}\text{ x }\frac{6}{22}=\frac{42}{484}=\frac{21}{242}$

PART 7:

The probability of randomly pulling a purple ball from the bag, returning it, and pulling a blue ball on your second pull =

$\frac{5}{22}\text{ x}\frac{7}{22}=\frac{35}{484}$