In circle A, marc BC is 71° and marc EF is 78°: What is m∠FDE? 35.5° 74.5° 39° 78°

Given:
We have arc BC is 71 degrees and arc FE is 78 degrees
Required:
We need to find the angle FDE
Explanation:
to find angle FDE
[tex]m\angle FDE=\frac{1}{2}(71+78)=74.5[/tex]Final answer:
angle FDE is 74.5 degrees