Question

how far will the body fall at t=6 and t=6.2?

Answer 1

EXPLANATION

Given the falling body equation:

$h=16t^2$

Substituting for t=6:

$h=16\cdot6^2=$

Computing the power:

$h=16\cdot36$

Multiplying numbers:

$h=576\text{ ft}$

Now, substituting for t=6.2:

$h=16\cdot(6.2)^2$

Computing the power:

$h=16\cdot38.44$

Multiplying numbers:

$h=615.04\text{ ft}$

Hence, the solutions are:

For t= 6s ---> h=576 ft

For t= 6.2s ---> h= 615.04 ft

Subtracting both distances:

$\Delta h=615.04-576=39.04_{\text{ }}ft$

Hence, the body will fall ≈ 39 ft between those seconds.