ANSWER
True
EXPLANATION
In the quadractic formula:
[tex]\begin{gathered} ax^2+bx+c=0 \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \end{gathered}[/tex]The discriminant is the part of the formula that's inside the square root: b² - 4ac. If this equals to zero, then we have in the formula that:
[tex]x=\frac{-b}{2a}[/tex]In a quadratic equation if there are real roots, then there are always two. If the discriminant is 0 then we know that there's one root, but with multiplicity 2.
Therefore, this statement is true.