Question

A side of the triangle below has been extended to form an exterior angle of 162º. Findthe value of x.

Answer 1

Notice that the exterior angle of 162 degrees and angle x are supplementary, therefore:

$x^{\circ}+162^{\circ}=180^{\circ}$

solving for x we get:

$\begin{gathered} x^{\circ}=(180-162)^{\circ} \\ x^{\circ}=18^{\circ} \end{gathered}$