Solution
Show that the following is true by mathematical induction for all natural numbers of n
[tex]2+7+12+17+....+(5n-3)=\frac{n(5n-1)}{2}[/tex][tex]\frac{n(5n-1)}{2}[/tex]when n = 1,
The claim is true for n = 1, a_1 = 2
[tex]\begin{gathered} 2=\frac{1}{2}(5(1)-1) \\ 2=\frac{1}{2}.4 \\ 2=2 \end{gathered}[/tex]Assume the claim is true for n , and look for n+1
[tex]2+7+....+5n-3+5(n+1)-3[/tex]The induction hypothesis is that the first n terms sum up to:
[tex]\frac{n(5n-1)}{2}[/tex]