Question

what is the final velocity of a 0.152 kg t-ball that has a force of 10 N applied for 0.18 seconds starting from rest?

Answer 1

Given:

The mass of the ball is m =0.152 kg

The force applied to the ball is F = 10 N

The initial velocity of the ball is

$v_{_i}=0\text{ m/s}$

The time taken is t = 0.18 s.

To find the final velocity of the ball.

Explanation:

The acceleration can be calculated as

$\begin{gathered} a=\frac{F}{m} \\ =\frac{10}{0.152} \\ =65.789\text{ m/s}^2 \end{gathered}$

The final velocity of the ball will be

$\begin{gathered} v_f=v_i+at \\ =0+65.789\times0.18 \\ =\text{ 11.84 m/s} \end{gathered}$

Thus, the final velocity is 11.84 m/s.