Ok, so
A line passes through the points (20,-14) and (4,-14). We are asked to find the equation of this line.
First, we're going to find the slope of the line.
For this, remember that:
Given two points (x1,y1) and (x2,y2), the slope (m) between them can be found using the equation:
[tex]m=\frac{y_2-y_1}{x_2-x_1}_{}[/tex]If we replace our values, we notice that:
[tex]\begin{gathered} x_1=20 \\ x_2=4 \\ y_1=-14 \\ y_2=-14 \end{gathered}[/tex]And replacing in the equation:
[tex]m=\frac{-14-(-14)}{4-20}=\frac{0}{-16}=0[/tex]The slope of our line is 0.
Now, given the slope "m" and one point (x1,y1), the equation in slope-intercept form can be found using the formula:
[tex]y=y_1+m(x-x_1)[/tex]Replacing (x1,y1) as (4,-14) and m=0:
[tex]\begin{gathered} y=-14+0(x-4) \\ y=-14 \end{gathered}[/tex]Therefore, the equation of the line is y=-14
