Given in the problem that the coordinates of the end points of a side of a rectangle is;
[tex]A(-3,6),B(-1,7)[/tex]
Each of the angles of a rectangle is 90 degrees. Let a line BC be perpendicular to line AB.
The slope of line AB is;
[tex]\begin{gathered} \text{Let;} \\ x_1=-3,y_1=6,x_2=-1,y_2=7 \\ m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{7-6}{-1-(-3)} \\ m=\frac{1}{2} \end{gathered}[/tex]
When the two lines are perpendiculat to each other, the product of their slopes is negative one.
Hence, the slope of line BC is;
[tex]\begin{gathered} m(\frac{1}{2})=-1 \\ m=-2 \end{gathered}[/tex]
Now, we can get the coordinate of point C (x,y). We have;
[tex]\begin{gathered} B(-1,7),C(x_2,y_2),m=-2 \\ -2=\frac{y_2-7}{x_2-(-1)} \\ \text{Let;} \\ x_2=5 \\ -2=\frac{y_2-7}{6} \\ y_2=-12+7 \\ y_2=-5 \\ C(5,-5) \end{gathered}[/tex][tex]D(3,-6)[/tex]
This is a rectangle because the two sides are parallel to each other and opposite sides are equal in length.