Respuesta :

We are given the following equation:

[tex]0.4(2x+\frac{1}{2})=3(0.2x+(-2))-4[/tex]

First, we will use the distributive property:

[tex]0.8x+0.2=0.6x+3(-2)-4[/tex]

Now, we solve the product 3(-2):

[tex]0.8x+0.2=0.6x-6-4[/tex]

Now, we add like terms:

[tex]0.8x+0.2=0.6x-10[/tex]

Now, we will subtract 0.6x from both sides:

[tex]\begin{gathered} 0.8x-0.6x+0.2=0.6x-0.6x-10 \\ 0.2x+0.2=-10 \end{gathered}[/tex]

Now, we will subtract 0.2 from both sides:

[tex]\begin{gathered} 0.2x+0.2-0.2=-10-0.2 \\ 0.2x=-10.2 \end{gathered}[/tex]

Now, we divide both sides by 0.2:

[tex]x=-\frac{10.2}{0.2}[/tex]

Solving the operation:

[tex]x=-51[/tex]

Therefore, the value of "x" is -51.

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