To determine the probability that both the chips are green:
[tex]\text{Probability =}\frac{\text{ number of required outcome}}{\text{ number of possible outcome}}[/tex][tex]\begin{gathered} G\text{reen =2} \\ B\text{lue }=\text{ 5} \\ \frac{Y\text{ellow = 8}}{} \\ \frac{\text{Total = 15}}{} \end{gathered}[/tex][tex]\begin{gathered} \text{Probability (gr}een)=\frac{\text{ number of gr}een}{total\text{ number}} \\ Pr(\text{green) =}\frac{2}{15}\text{ } \\ Pr(\text{both are gre}en)=\frac{2}{15}\text{ x }\frac{2}{15}=\frac{4}{225} \end{gathered}[/tex]Therefore the probability that both the chips are green =4/225
Hence the correct answer is Option A