Given the equation:
[tex]\frac{5}{9}(f-32)=25[/tex]to solve for 'f', first we have to move the 5/9 to the other side of the equation. Since it's multiplying the factor (f-32), it will pass to the other side dividing 25:
[tex]\begin{gathered} \frac{5}{9}(f-32)=25 \\ \Rightarrow f-32=\frac{25}{\frac{5}{9}}=45 \\ \Rightarrow f-32=45 \end{gathered}[/tex]next we move the 32 to the right side of the equation. Since it's substracting, we move it to the other side adding to get the following:
[tex]\begin{gathered} f-32=45 \\ \Rightarrow f=45+32=77 \\ f=77 \end{gathered}[/tex]therefore, f=77
