If the triangle is a 45-45-90, then it must be an isosceles right triangle, therefore 15 must be equal to x, let's check that out using pythagorean theorem:
[tex]\begin{gathered} (15\sqrt[]{2})^2=15^2+x^2 \\ x=\sqrt[]{(15\sqrt[]{2})^2-15^2} \\ x=\sqrt[]{450-225} \\ x=\sqrt[]{225} \\ x=15 \end{gathered}[/tex]Therefore, we can conclude that Tameka is correct. It is a 45-45-90 triangle.
Let's check the perimeter:
[tex]P=15+15+15\sqrt[]{2}=30+15\sqrt[]{2}\ne45\sqrt[]{2}[/tex]Thus, the only correct statements are:
B. Tameka is correct. It is a 45-45-90 triangle
D. The measure of the remaining leg is also 15