Question

On the coordinate plane, what is the distance (to the nearest tenth) between (11.-3) and (4,7)?A 10.9 unitsB. 12.2 unitsC. 14.4 unitsD. 17 units

Answer 1

The distance on the coordinate plane between the two points is 12.2 units

Here, we want to calculate the distance between two points on the coordinate plane

To get this, we are going to use the distance formula

Mathematically, we have this as;

$\begin{gathered} D=\text{ }\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \\ (x_1,y_1)\text{ = (11,-3)} \\ (x_2,y_2)\text{ = (4,7)} \\ \\ D\text{ = }\sqrt[]{(4-11)^2+(7-(-3)^2} \\ D\text{ = }\sqrt[]{(-7)^2+(10)^2} \\ \\ D\text{ = }\sqrt[]{149} \\ \\ D\text{ = 12.2 UNITS} \end{gathered}$