Solution
Factorise the equation
[tex]4x^2-x-5[/tex]Step 1: Break the expression into groups
[tex]\begin{gathered} 4x^2-x-5 \\ 4x^2+4x-5x-5 \end{gathered}[/tex]Step 2: factorise the expression
[tex]\begin{gathered} 4x^2+4x-5x-5 \\ 4x(x+1)-5(x+1) \\ (x+1)(4x-5) \end{gathered}[/tex]Therefore the answer is
[tex](x+1)(4x-5)[/tex]