To answer this question, we can proceed as follows:
1. We have that the scale is 1 inch represents 30 miles.
Then, with this factor we can find the actual area of the park in square miles, as follows:
[tex]4in\cdot\frac{30\text{miles}}{1\text{inch}}=\frac{4in\cdot30miles}{1inch}=120\text{miles}[/tex]We use the scale factor to find the actual value for the length of 4 inches. We can use the same for the width of the map:
[tex]6in\cdot\frac{30miles}{1inch}=\frac{6in\cdot30miles}{1inch}=180\text{miles}[/tex]Now, the actual area of the park in square miles is:
[tex]A_{\text{park}}=120\text{miles}\cdot180\text{miles}=21600\text{miles}^2[/tex]Therefore, the actual area of the park is 21,600 square miles.