Question

I know that triangle AEB angles are 80, 52, 48 and triangle ADC angles are 80, 51, 49 that being said would the answer be no triangles are similar since they don’t have the same angles or did I do this wrong.

Answer 1

Given:

$\begin{gathered} \angle EAB=\angle DAC=80^{\circ} \\ \angle AEB=52^{\circ} \\ \angle ACD=48^{\circ} \end{gathered}$

Now consider the triangle EAB and triangle CDA,

it is observed that,

$\angle DAC\approx\angle EAB$

But no other angles are similar.

So, triangle EAB is not similar to triangle CDA

Similarly for, Triangle BAE and CAD, triangle AEB and ADC , triangle DCA and BAE only one angle is similar.

Hence, it is concluded that no triangles are similar.