Given:
a.) The new height is 100.05% of what it was the previous year.
b.) The average male's height was 54 inches in 1548.
For us to be able to determine the average height of a male in 2008, we will be using the geometric sequence formula:
[tex]A_n\text{ = }A_1(r)^{n-1}[/tex]Where,
An = The average height of a male in 2008
A1 = 54 inches
r = 100.05% = 100.05/100 = 1.0005
n = (2008 - 1548) + 1 = 460 + 1 = 461
We get,
[tex]A_n\text{ = }A_1(r)^{n-1}[/tex][tex]A_n\text{ = }(54)(1.0005)^{461-1}\text{ = }(54)(1.0005)^{460}[/tex][tex]=(54)(1.2585276666222281763001496826748)[/tex][tex]=\text{ }67.960493997600321520208082864439[/tex][tex]\text{ }\approx\text{ 67. 96 inches}[/tex]Therefore, in 2008, the average height of a male will be 67.96 inches.