Question

An angle measures 3° more than two times its complement x please explain

Answer 1

Solution:

Given that;

An angle measures 3° more than two times its complement x.

Let the larger angle be y

$x+y=90\degree$

The angle measures 3° more than two times its complement, i.e.

$y=(2x+3)\degree$

Then,

$\begin{gathered} x+y=90\degree \\ x+(2x+3)\degree=90\degree \\ x\degree+2x\degree+3\degree=90\degree \\ 3x\degree=90\degree-3\degree \\ 3x=87\degree \\ x=\frac{87\degree}{3} \\ x=29\degree \end{gathered}$

The smaller angle, x is 29 degrees

The larger angle is

$y=2x+3=2(29)+3=58+3=61\degree$

The larger angle, y is 61 degrees

The total is

$x+y=29+61=90\degree$

The total is 90 degrees.