The perimeter of a rectangle is given by:
[tex]P=2L+2W[/tex]Where L is the length and W is the width.
By replacing the given information we have:
[tex]112=2(5y)+2(4y+2)[/tex]Now, we have to solve for y as follows:
[tex]\begin{gathered} \text{Apply the distributive property} \\ 112=10y+2\cdot4y+2\cdot2 \\ 112=10y+8y+4 \\ 112=18y+4 \\ 112-4=18y \\ 108=18y \\ y=\frac{108}{18} \\ y=6 \end{gathered}[/tex]Replace the y-value into the BC side expression and solve:
[tex]\begin{gathered} BC=4y+2 \\ BC=4(6)+2 \\ BC=24+2 \\ BC=26 \end{gathered}[/tex]