Solution
- To solve the question, we should bring the integrals with the same lower bound together.
- Thus, we have:
[tex]\begin{gathered} \int_{-2}^2f(x)+\int_2^5f(x)-\int_{-2}^{-1}f(x) \\ \\ \int_{-2}^2f(x)-\int_{-2}^{-1}f(x)+\int_2^5f(x) \\ \\ \int_{-1}^2f(x)+\int_2^5f(x) \\ \\ =\int_{-1}^5f(x) \end{gathered}[/tex]Final Answer
The answer
[tex]\begin{gathered} a=-1 \\ b=5 \end{gathered}[/tex]