Solution
We have the following expression:
[tex]y=2x^2-16x+24[/tex]y= height of the pool and x= time in seconds
And we know that the turtle path is given by:
[tex]y=-x-1[/tex]We can do the following:
[tex]2x^2-16x+24<-x-1[/tex]And we can solve for x on this way:
[tex]2x^2-15x+25<0[/tex]We can factorize and we got:
[tex](2x-5)(x-5)<0[/tex]And we can do the following to solve the problem:
Then we can conclude that the answer is:
5/2 < x < 5
Between 5/2 and 5 seconds the swimmer dive is below the turtle that represent 5/2 seconds