Question

A 12-liter container has a pressure of 3 atmospheres.The container is sent underground, with resulting compression into 6 L.Applying Boyle's Law, what will the new pressure be?

Answer 1

Step 1

Given;

$\begin{gathered} P_1=3atm \\ v_1=12l \\ v_2=6l \\ p_2=? \end{gathered}$

Step 2

Boyle's law is given as

$p_1(v_1)=p_1(v_2)$$\begin{gathered} 3(12)=6(p_2) \\ 36=6p_2 \\ p_2=\frac{36}{6}=6atm \end{gathered}$

Answer;

$The\text{ new pressure = 6atm}$