The formula for caluculating the compound amount is
For this question,
p = $10,205.3
r = 4.434% = 0.004434
t = 6
A.
If interest is compounded monthly,
n = 12
[tex]\begin{gathered} A\text{ = 10205.3(}1+\frac{0.004434}{12})^{12(6)} \\ A=10205.3(1+0.003695)^{72} \\ A=\text{ 10205.3(}1.003695)^{72} \\ A=10205.3(1.30414) \\ A\text{ =\$ 13,309}.22 \end{gathered}[/tex]B.
If interest is compounded weekly:
n = 52
[tex]\begin{gathered} A\text{ = }10250(1+\frac{0.004434}{52})^{52\text{ x 6}} \\ A=10250.3(1.000085)^{312} \\ A=\text{ 10205.3}(1.3046) \\ A\text{ = \$1}3,314.23 \end{gathered}[/tex]C. If interest is compounded continuously:
n =365,
[tex]\begin{gathered} A\text{ = 10,205.3(1 + }\frac{0.004434}{365})^{365\text{ x 6}} \\ A=10,205.3(1+0.000012147)^{2190} \\ A=10,205.3(1.000012147)^{2190} \\ A=10,205.3(1.304766) \\ A=\text{ \$}13,315.53 \end{gathered}[/tex]Hence,
If interest is compounded monthly, the value is $13,309.22
If interest is compounded weekly, the va;ue is $13,314.23
And If interest is compounded continuously, the value is $13,315.53.