Given the triangle, find x to the nearest one hundreds

According to the trigonometric relations for a right triangle, we have:
[tex]\begin{gathered} \tan30\degree=\frac{x}{12} \\ x=12\cdot\tan30\degree \\ x=12\cdot\frac{\sqrt{3}}{3} \\ x=4\cdot\sqrt{3}\approx6.93 \end{gathered}[/tex]