a gun with a muzzle velocity of 100m/s is fired horizontally from a tower neglecting air resistance how far downrange will the bullet be 1 s later

Respuesta :

While the bullet is in the air, there are no horizontal forces acting on it (we're neglecting air resistance and there is gravity, but that is a vertical that no affect x-movement). Therefore, the acceleration of the bullet in the x-direction can be solved as a rectilinear motion problem.

we have the next information

v=100 m/s

t=1 s

We will use the next formula

[tex]v=\frac{d}{t}[/tex]

where v is the velocity, d is the distance and t is the time

we substitute the values given

[tex]100=\frac{d}{1}[/tex]

then we isolate the d

[tex]d=100\cdot1=100m[/tex]

After 1 second, the bullet will be 100 m away.

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