Question

Write each expresión as a sum or difference of multiples of logarithms , assume the variables represent postpone numbers

Answer 1

Solution:

Given;

$\log_6\frac{4x}{3}$

Recall the subtraction property of logarithm;

$\log_ca-\log_cb=\log_c\frac{a}{b}$

Thus;

$\log_6\frac{4x}{3}=\log_64x-\log_63$

ANSWER:

$\log_64x-\log_63$