find the measure of each angle I'm really confused about this

SOLUTION
To solve this question, we first need to know some things:
1. The two angles are equal where the unequal sides meet.
(Angle E and Angle are equal)
2. Sum of angles in a quadrilateral are 360 degrees
[tex]\angle F+\angle E+\angle H+\angle G=360^O[/tex][tex]\angle E=\angle G=x^o[/tex][tex]\angle M=90^O[/tex][tex]\angle F=150^O[/tex][tex]\begin{gathered} \angle F+\angle E+\angle H+\angle G=360^O \\ 150^o+x^o+90^o+x^o=360^o \\ \end{gathered}[/tex][tex]\begin{gathered} 240^o+2x^o=360^o \\ 2x^o=360^o-240^o \\ 2x^o=120^o \\ x^o=\frac{120}{2} \\ x^o=60^o \end{gathered}[/tex][tex]x^o=\angle G=60^O[/tex]