Given equations are
[tex]y=-2x-7[/tex][tex]2y-x=1[/tex][tex]\text{ Substitute y=-2x-7 in equation 2y-x=1 as follows.}[/tex][tex]2(-2x-7)-x=1[/tex]Multiplying 2 and (-2x-7), we get
[tex]2(-2x)-2\times7-x=1[/tex][tex]-4x-14-x=1[/tex][tex]-5x-14=1[/tex]Adding 14 on both sides, we get
[tex]-5x-14+14=1+14[/tex][tex]-5x=15[/tex]Multiplying both sides by (-5), we get
[tex]-\frac{5x}{-5}=\frac{15}{-5}[/tex][tex]x=-3[/tex][tex]\text{ Substitute x=-3 in the equation y=-2x-7 as follows.}[/tex][tex]y=-2(-3)-7[/tex][tex]y=6-7[/tex][tex]y=-1[/tex]Hence we get (x, y)= ( -3, -1).
Option D) is correct.