Respuesta :

Given equations are

[tex]y=-2x-7[/tex][tex]2y-x=1[/tex][tex]\text{ Substitute y=-2x-7 in equation 2y-x=1 as follows.}[/tex]

[tex]2(-2x-7)-x=1[/tex]

Multiplying 2 and (-2x-7), we get

[tex]2(-2x)-2\times7-x=1[/tex]

[tex]-4x-14-x=1[/tex]

[tex]-5x-14=1[/tex]

Adding 14 on both sides, we get

[tex]-5x-14+14=1+14[/tex]

[tex]-5x=15[/tex]

Multiplying both sides by (-5), we get

[tex]-\frac{5x}{-5}=\frac{15}{-5}[/tex]

[tex]x=-3[/tex]

[tex]\text{ Substitute x=-3 in the equation y=-2x-7 as follows.}[/tex][tex]y=-2(-3)-7[/tex]

[tex]y=6-7[/tex][tex]y=-1[/tex]

Hence we get (x, y)= ( -3, -1).

Option D) is correct.

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