If a, b, and c are the 3 sides of a right triangle and c is the longest side, then
[tex]c=\sqrt[]{a^2+b^2}[/tex]Let a = 30, b = 40, then
[tex]\begin{gathered} c=\sqrt[]{(30)^2+(40)^2} \\ c=\sqrt[]{900+1600} \\ c=\sqrt[]{2500} \\ c=50 \end{gathered}[/tex]The third number should be 50