Answer:
$612.75
Explanation:
First, convert 43 minutes into hours
[tex]43\text{ min}\times\frac{1\text{ hour}}{60\text{ min}}=0.716\text{ hours}[/tex]Then, the total number of hours in the month is
[tex]0.716\text{ hours }\times30\text{ days = 21.5 hours}[/tex]Then, 1,500 W is equivalent to 1.5 kW, so the total kWh is equal to
[tex]1.5kW\times21.5\text{ hours = 32.25 kWh}[/tex]Now, we can calculate the cost as follows
[tex]33.25\text{ kWh}\times\frac{19\text{ \$}}{1\text{ kWh}}=612.75\text{ }[/tex]Therefore, the answer is $612.75