Question

a cone shaped block has a slant height of 6 in and a radius of 4 in. how many square inches of paper would it take to cover the surface?

Answer 1

The formula to find the surface area of a cone is

$\begin{gathered} SA=\pi rs+\pi r^2 \\ \text{ Where} \\ SA\text{ is the surface area} \\ r\text{ is the radius and} \\ s\text{ is the slant height of the cone } \end{gathered}$

So, in this case, you have

$\begin{gathered} r=4in \\ s=6in \end{gathered}$$\begin{gathered} SA=\pi(4in)(6in)+\pi(4in)^2 \\ SA=24\pi in^2+16\pi in^2 \\ SA=40\pi in^2 \\ SA=125.66in^2 \end{gathered}$

Therefore, it would take 125.66 square inches to cover the surface of the cone.