Respuesta :

As per given by the solution,

There are given that the equation,

[tex]\begin{gathered} s(x)=2x+2 \\ t(x)=-2x^2-2 \end{gathered}[/tex]

Now,

According to the question, find the value of t(s(-4)).

Then,

First find the value of s(-4);

So,

The given equation is ,

[tex]s(x)=2x+2[/tex]

Put the value of x =-4 into above equation,

Then,

[tex]\begin{gathered} s(x)=2x+2 \\ s(-4)=2\times(-4)_{}+2 \\ s(-4)=-8+2 \\ s(-4)=-6 \end{gathered}[/tex]

Now,

For finding the value of t(s(-4)):

From the second equation,

[tex]t(x)=-2x^2-2[/tex]

In above equation, put the value of s(-4) instead of x.

So,

[tex]\begin{gathered} t(x)=-2x^2-2 \\ t(s(-4))=-2\times(-6)^2^{}-2 \\ t(s(-4))=-2\times36-2 \\ t(s(-4))=-72-2 \\ t(s(-4))=-74 \end{gathered}[/tex]

Hence, the value of t(s(-4)) is -74.

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