The functions s and t are defined as follows.s(x) = 2x + 2t(x)=-2x²-2Find the value of t(s(-4)).

As per given by the solution,
There are given that the equation,
[tex]\begin{gathered} s(x)=2x+2 \\ t(x)=-2x^2-2 \end{gathered}[/tex]Now,
According to the question, find the value of t(s(-4)).
Then,
First find the value of s(-4);
So,
The given equation is ,
[tex]s(x)=2x+2[/tex]Put the value of x =-4 into above equation,
Then,
[tex]\begin{gathered} s(x)=2x+2 \\ s(-4)=2\times(-4)_{}+2 \\ s(-4)=-8+2 \\ s(-4)=-6 \end{gathered}[/tex]Now,
For finding the value of t(s(-4)):
From the second equation,
[tex]t(x)=-2x^2-2[/tex]In above equation, put the value of s(-4) instead of x.
So,
[tex]\begin{gathered} t(x)=-2x^2-2 \\ t(s(-4))=-2\times(-6)^2^{}-2 \\ t(s(-4))=-2\times36-2 \\ t(s(-4))=-72-2 \\ t(s(-4))=-74 \end{gathered}[/tex]Hence, the value of t(s(-4)) is -74.